Order of Operations in Grade V

Hi Children! While doing mathematical operations and to get the correct answer for operations on rational numbers we need to learn proper order of the operators. In order to learn order of operations in math, we need to remember BODMAS taken from CBSE, where
B stands for Bracket
O stands for Of operator
D stands for Division
M stands for Multiplication
A stands for Addition
S stands for subtraction.
This means that first all the operations in the brackets are to be performed followed by operator "of", and then we check if there exist division operation, we perform division. Then we check the expression for multiplication, if there is a multiplication operator, and then we multiply. Then we check for addition in the expression and add the terms followed by subtraction to be done at the last.
Let us understand it more clearly through an example:
 Solve 20 - 2 * 10/2 + (6 - 2)
To solve the above expression we first look at the braces and solve as follows:
 (6 - 2) = 4, so the given expression becomes as:
   = 20 - 2 * 10/2 + 4
 Now we take into consideration the operation of division and perform 10 / 2
 We get 10 / 2 = 5; now put this value in the above expression we get:
   20 - 2 * 5 + 4
 Now next comes the turn of multiplication operator, we get:
  2 * 5 = 10,
 Similarly now we replace this value in the above expression, we get:
 = 20 - 10 + 4
 Now we add 4 to -10 and get 10 + 4 = -6
 = 20 -6
 = 14 Ans.
In this way various mathematical expressions can be solved by ordering operations. 

 

In next post we will talk on Problems on sum of angles for Grade V. For more information on linear equations, you can visit our website

How to solve mathematical Expressions:

While dealing with the mathematical numbers and various mathematical operations, we  come across various mathematical  expressions for example - algebraic expression which looks very complicated and are not so easy to be solved and came across cbse syllabus many times. To solve such expressions, we need to follow certain rules to get the correct solution.

Whenever we are given some mathematical equations to solve, These equations are to be solved in a particular order in order to get the proper solution to the expressions. This Order of Operations includes the following sequence:
1  parenthesis, (called Braces)
2. Of
3. Division
4. Multiplication
5. Addition
6. Subtraction.
 This sequence is remembered by the student as an acronym- BODMAS
First of all the braces are opened ,solved and then removed to make the equation in the simple form.(Learn more about mathematical expressions here),
 After every step, the equation / expression takes a simpler form,
Let us consider some  examples:
Solve the numerical expression 15 - [ 11 - 8 ÷ ( 17 + 3 * 2 - 19 )
 Here we solve the brackets in the order ( ), followed by , then [ ]
= 15 -  [ 11 -  8 ÷ (17 + 6 - 19) ]
 we have 17 + 6 - 19 = 4
 = 15 - [ 11 - 8 ÷ 4 ]
 = 15 - [ 11- 2 ]    As 8 ÷ 4 = 2
 = 15 - 9
= 6 Ans.
Solve the given numerical expression:
 11/2 of (2/3 - 3/5) + 1/2 ÷ 5/11-------(1)
 Here , following the heirachy of the above simplification procedure, first we solve:
     (2/3 - 3/5)
l.c.m. of 3 & 5 is 15, so by making the denominator =15 we get
 = ( 2 * 5 - 3 * 3 ) / 15
 = ( 10 -  9 )/15
= 1/15
  Putting this value in ( 1) we get
=  11/2 of  1/15  + 1/2 ÷ 5/11------ (2)
  In next step we solve "of "
  11/2 of  1/15
  = 11 /30
 Putting this value 11/30 in  (2) we get
 = 11/30    + 1/2 ÷ 5/11 --------- (3)
In next step we solve " ÷ "
 1/2 ÷ 5/11
= 1/2 * 11/5
= 11 / 10
Putting this value 11/ 10 in  (3) we get
 11 / 30  + 11 / 10
 Now taking L.C.M. of 10 and 30 = 30,
we get
= ( 11 + 11* 3 ) /30
= ( 11+ 33 ) / 30
= 44 / 30
Now converting into simplest form , we divide Numerator & denominator  2, w get
 = 22 / 15 Ans

 Solve the  Following:
21 -( 12 - 6 ÷ 3)------- (1 )
 In this given expression, we first consider the brackets,
 We solve the bracket
( 12 - 6 ÷ 3),
Now in Bracket , we first take division i. e.
6 ÷ 3 =2,
= (12 -2)
 = 10
Putting this value in eqn (1) we have
= 21- 2
= 19 Ans

In this way, by following proper procedure , order of operations, opening parenthesis systematically required  for solution, any given numerical expression can be solved and if you want to know about Math Blog on Probability and Statistics then refer Internet,Read more maths topics of different grades such as Mathematical Reasoning in the next session here.