Variables and Expressions Examples

In the previous post we have discussed about Subtraction of Fractions Calculator and In today's session we are going to discuss about Variables and Expressions Examples. When we study about the Algebra, the basic units of algebra are the constants and the variables. The equations are basically formed by the combination of  Variables And Expressions. Different terms, which we observe are combined with the help of the mathematical operators + and -.
To study about Variables And Expressions Examples, let us look at the following statement:
If two times of any number is added to 4, the result is 16.
In order to solve the given statement, we start as follows. Let us consider the variable x as the unknown number. Now when we talk about the two times of the unknown number, it simply means that the variable x  is multiplied by the number 2.
Further  we have that a number 4 is added to it, so the two terms will be 2x and 4, which we will be adding by the operator +. Thus the equation so formed by the statement will be as follows :
2x + 4 = 16
 Here we have the expression 2x + 4, where the terms of the equation are 2x and 4.
The value of x will be calculated by  solving the given equation. Thus we will get :
2x + 4 = 16
We will take 4 to another side of the equation and it will change from + 4 to – 4. So we get the equation as :
2x = 16 – 4
Or 2x= 12
 Now we observe that the left side of the equation is 2 * x, so we will take 2 to another side of the equation  by replacing the  multiplication with the relation of division. Thus we get :
X = 12 / 2
Or we write  x = 6 is the solution for the given equation.

 There  are different Properties Of Real Numbers like closure property, associative property, Commutative Property, Identity Property etc.  Icse Sample Papers 2013 are also available online.

Subtraction of Fractions Calculator

In the previous post we have discussed about Square Root Property and In today's session we are going to discuss about Subtraction of Fractions Calculator. Generally when we talking about the calculator then first thing came in our mind is that it is a kind of device that usually performs arithmetical calculation on numbers. Normally a simple calculator can perform multiply, divide, add and subtract percent related calculation and so on. If we talking about more advance calculator then they can also perform exponent, root and log related calculation to solve real world problem. Here we are going held a discussion on the topic of Subtracting Fractions Calculator.

It is also a kind of calculator that can perform the subtraction between two fractional values. To understand the concept of fractional calculator we need to understand the concept of fractional numbers and arithmetical operation that is subtraction. Fractional values are kind of number that shows two integer value in the ration form that is in the form of numerator and denominator. Suppose m and n are two integers then they can be represented as m / n. Here we need to perform subtraction between these fractional values. Subtraction can be define as a basic arithmetical operation that perform the reduction In value from another value. Now we can describe the process of Subtracting Fractions Calculator.

I ) For performing subtraction between fractional value first we need to calculate HCF of denominator values of both fractional values.

II ) After that divide the Calculated HCF value by each denominator value individually.

III) After performing above given step multiply the each result with their numerator value.

IV ) In last perform the subtraction between the obtained value and if required then simplify them.

The above given steps can easily describes the functionality of Subtracting Fractions Calculator.

In chemistry the concept of Ribonucleic Acid can be describe as a biologically molecule which is made up of long chain of nucleotide units. The Indian certificate of secondary education board provides previous years sample papers which is known as icse 2013 question papers.

Square Root Property

In mathematics, we will solve the square using different method. Here we will see Square Root Property and also see how to solve square root. Square root can be defined as a number in mathematics that is the multiplication of that same no twice, as (s) could be the square root of (t) like :

[s2 = t]

[√t = s]

Square root is represented by the symbol √r and √ is said to be radical sign.

In order to solve square root we need to follow some of the steps which are mention below:

Step 1:- To solve square root first we have to divide the digit which has to be square root into pairs, from the decimal point.

Step 2:- Then we have to draw the line over the pair of the digits.

Step 3:- Then calculate largest number such that the square root is same to or less than the next term pair.

Step 4:- Then we have to set the number over left side and also above the next digit pair.

Step 5:- Now we have to square a number and then subtract that number from the next digit pair.

Step 6:- Then after spread the bracket present in left side and then multiply the last number by 2, than put that number on left of the difference we have just find and leave the empty decimal place next to it. (know more about Square Root, here)

Step 7:- Now put the next term down and right to the difference.

Step 8:- Now we have to calculate the largest number to fill the blank space such that the number is times the number already exists, and should be less then the current difference.

Step 9:- Now we have to subtract the number just found.

Step 10:- And then we have to repeat all steps untill we get the result.

Using these properties we can easily solve the square root.

Reverse Osmosis System can be ideal for such applications as spot performance. From icse books download we get more information about reverse osmosis system and In the next session we will discuss about 

Subtraction of Fractions Calculator. 

rational expressions applications

In the previous post we have discussed about Fibonacci Numbers and In today's session we are going to discuss about rational expressions applications. Rational expressions applications defines the uses of rational expressions in different area of mathematics. A rational expression is expressed as the ratio of polynomial equations as:
p > 2 + q / p – q > 2. These kind of expressions are known as relational expression. There are several formulas that having the rational expression and for solving it multiply both the side of equation with the LCD that is used for eliminate the denominators of the expression.
We can define it by a simple example as if there is an equation that express a line (-2 , 4) and have the slope 3 / 2 that is written by a rational expression (y – 4) / ( x + 2) = 3 / 2.
Now we cam solve it as (y – 4) / (x + 2) = 3 / 2
Multiply both the side of expression with the LCD (x + 2) as;
(x + 2) (y – 4) / (x + 2) = (x + 2) 3 / 2.
In this step solve all the calculations as y – 4 = 3 x / (2 + 3);
Now it will be more simplified as y = 3 x / (2 + 3 + 4)
Y = 3 x/ (2 + 7) , this expression gives a line equation for particular coordinates. (know more about Rational function, here)
There are numerous expression in mathematics as relation between rate, time and distance is also define by d / t = r where d is the distance, t is time taken to cover that distance and r describe the rate of speed.
Valence Electron Configuration is studied in atomic physics and quantum chemistry that define the configuration of electrons.
Central board of secondary education provide cbse syllabus for class 1 that mention all the topics come into the respective session.

Fibonacci Numbers

In the previous post we have discussed about Ratios and Proportions and In today's session we are going to discuss about Fibonacci Numbers. 

Fibonacci Numbers are describe as the sequencing of numbers that follow the linear recurrence rule. We can also explained it by a simple expression as if Xn is a function then according to the linear recurrence rule (Xn)  where value of n is from 1 to infinity.

This will be expressed as  Xn = x n-1 + x n -2 + x n-3 ….

In the above expression if the value of n is 1 or 2 then X1 = X2 = 1 and in case of X0 is is equal to one.

When we present the Fibonacci numbers for the values of n = 1 , 2 and so on then it will show as 1,1 ,2 ,3 ,5 , 8 ,13 , 21 ,34 …. So on.

We can define some of the problems that are defined by the Fibonacci numbers series as there is a problem stated as one male and one female those are born on first January and if all the months having the equal number of days then find the number of pairs that are produce after the birth of first pair in next two months and when a pair have the age of two months then it produce another pair and this pair also generate the another pair after two months and no pair dies.

So we have to find the number of pairs after the period of one year?

So these kind of problems are solved by Fibonacci numbers.

For solving the problems like Subtracting Fractions With Unlike Denominators, need to make the denominators of both the fractions same and for this we have to calculate the LCM that is stated as least common multiple and then we calculate the answer of the given problem. (know more about Fibonacci Numbers, here)

Cbse Board Papers are organized by the central board of secondary education (CBSE board) in month of march of every year for the students.

Ratios and Proportions

A ratio that is used to show the relation between two or more values. For example: if there are 12 pencils and 17 pens then we can write the ratio as: 12:17; In other word for every 12 pencils there are 17 pens. If any equation written in the form of P / Q = R / S, here both the ratios are equal are said to be proportion. For example (5 / 9) = (20 / 32). Let's see how find the Ratios and Proportions? Steps for ratio and proportions are shown below:
Step1: First we have two values for which we have to find the relation.
Step2: Then we find the relation in both the values.
Step3: Let we have two proportion sets, these two ratios are equal to each other. In one ratio, the quantities of two proportions do not fulfill, so we use cross multiplication and solve the equation and fulfill the quantities. There are different ways to find the ratios and proportions.
If 60 books for 32 students that can be represented in the ratio as 60:32. Now set the second ratio for another larger group of students, assume that the numbers of books move in the numerator and the numbers of students move in the denominator. Here we don’t know the total number of students. (know more about Ratios and Proportions, here)
Here assume the number of students be ‘U’. The total number of students is 42, and then the ratios of students are U / 42. Now we set these ratios according to the definition of ratio and proportion. So the ratio is:
=> (60 / 32)= U / 42,
Now find these ratios with the help of cross multiplication:
When we cross multiply these ratios we get:
⇒(60) (42) = (32) (U), Now solve these values for ‘U’.
⇒2520 = 32 U, here we find the value of ‘U’.
⇒32 U = 2520
⇒U = 2520 / 32
⇒U = 78.75;
After solving we get the value of U = 78.75;
There are 78.75 books for 42 students.

Surface Area of a Cylinder Formula is given as:
Surface area of cylinder = 2 * pi * r² + 2 * pi * r * h. We get new information about all grades syllabus in cbse syllabus 2013 and In the next session we will discuss about Fibonacci Numbers. 

  

Greatest Integer Function

In the previous post we have discussed about How to Deal with Ordered Pair Problems and In today's session we are going to discuss about Greatest Integer Function. 

Greatest Integer Function gives the highest integer number that is lies among the several numbers. We can also simplify the statement as ,it will give the highest number and all other number are lesser or equal to the given number. Sometimes we call the floor function of integer numbers. It will be expressed by a big bracket as[ ].

We can explain it is the process of finding number that have less than and equal value among the given number for a given integer value. So according to the definition of greatest integer function that is stated for the integer number will provide the number equal to the given number. When we find the greatest integer and when we find for any non integer number then in that case it will give only the integer part of that number and remove the decimal part. (know more about Greatest Integer Function, here)

We define it by some examples as, Find the greatest integer function of 7?

Solution: [7] = 7.

Explanation: As the given number is an integer number, hence the closest integer number to the left of the given number is the same number.

Find the greatest integer function of 4.7?

Solution: [4.7] = 4

Explanation: As the closest integer number to the left of the given number on the number line is 4.

 Find the greatest integer function of -3.4?

Solution: [-3.4] = -4,

Explanation: As the closest integer number to the left of the -3.4 is -4

According to Van Der Waals Equation, it states for composition of fluid that made by the particles that have a non zero volume and also for a pair wise inter particle force that is an attractive force .

Cbse Sample Papers 2013 provided by the central board of secondary education to the students for help them in preparation of examination.