A ratio that is used to show the relation between two or more values. For example: if there are 12 pencils and 17 pens then we can write the ratio as: 12:17; In other word for every 12 pencils there are 17 pens. If any equation written in the form of P / Q = R / S, here both the ratios are equal are said to be proportion. For example (5 / 9) = (20 / 32). Let's see how find the Ratios and Proportions? Steps for ratio and proportions are shown below:
Step1: First we have two values for which we have to find the relation.
Step2: Then we find the relation in both the values.
Step3: Let we have two proportion sets, these two ratios are equal to each other. In one ratio, the quantities of two proportions do not fulfill, so we use cross multiplication and solve the equation and fulfill the quantities. There are different ways to find the ratios and proportions.
If 60 books for 32 students that can be represented in the ratio as 60:32. Now set the second ratio for another larger group of students, assume that the numbers of books move in the numerator and the numbers of students move in the denominator. Here we don’t know the total number of students. (know more about Ratios and Proportions, here)
Here assume the number of students be ‘U’. The total number of students is 42, and then the ratios of students are U / 42. Now we set these ratios according to the definition of ratio and proportion. So the ratio is:
=> (60 / 32)= U / 42,
Now find these ratios with the help of cross multiplication:
When we cross multiply these ratios we get:
⇒(60) (42) = (32) (U), Now solve these values for ‘U’.
⇒2520 = 32 U, here we find the value of ‘U’.
⇒32 U = 2520
⇒U = 2520 / 32
⇒U = 78.75;
After solving we get the value of U = 78.75;
There are 78.75 books for 42 students.
Surface Area of a Cylinder Formula is given as:
Surface area of cylinder = 2 * pi * r2 + 2 * pi * r * h. We get new information about all grades syllabus in cbse syllabus 2013 and In the next session we will discuss about Fibonacci Numbers.
Step1: First we have two values for which we have to find the relation.
Step2: Then we find the relation in both the values.
Step3: Let we have two proportion sets, these two ratios are equal to each other. In one ratio, the quantities of two proportions do not fulfill, so we use cross multiplication and solve the equation and fulfill the quantities. There are different ways to find the ratios and proportions.
If 60 books for 32 students that can be represented in the ratio as 60:32. Now set the second ratio for another larger group of students, assume that the numbers of books move in the numerator and the numbers of students move in the denominator. Here we don’t know the total number of students. (know more about Ratios and Proportions, here)
Here assume the number of students be ‘U’. The total number of students is 42, and then the ratios of students are U / 42. Now we set these ratios according to the definition of ratio and proportion. So the ratio is:
=> (60 / 32)= U / 42,
Now find these ratios with the help of cross multiplication:
When we cross multiply these ratios we get:
⇒(60) (42) = (32) (U), Now solve these values for ‘U’.
⇒2520 = 32 U, here we find the value of ‘U’.
⇒32 U = 2520
⇒U = 2520 / 32
⇒U = 78.75;
After solving we get the value of U = 78.75;
There are 78.75 books for 42 students.
Surface Area of a Cylinder Formula is given as:
Surface area of cylinder = 2 * pi * r2 + 2 * pi * r * h. We get new information about all grades syllabus in cbse syllabus 2013 and In the next session we will discuss about Fibonacci Numbers.
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